In the figure given below, the position time graph of a particle of mass 0.1kg is shown. The impulse at t=2 sec is

Options

A. `0.2kgms^(-1)`
B. `0.02kg ms^(-1)`
C. `0.1kgms^(-1)`
D. `0.4kg ms^(-1)`

Answer

a

Explanation

From the graph it is clear that upto `t = 2.0 s` the body moves with a constant velocity = slope of
position time graph ` =(4)/(2) = 2 m//s` After `t = 2.0 s`
position time graph is parallel to time axis which means that the body comes to rest
`:.` Change in velocity ` = dupsilon = 2m//s`
Impulse = change in momentum
` = dp = m dupsilon = 0.1 xx 2 = 0.2 kgms^(-1)` .