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A block is kept on a frictionless inclin...

A block is kept on a frictionless inclined surface with angle of inclination `alpha`. The incline is given an acceleration 'a' to keep the block stationary. Then a is equal to

A

`g tan alpha`

B

`g`

C

`g cosec alpha`

D

`g//tan alpha`

Text Solution

Verified by Experts

The correct Answer is:
a

The block will remain stationary when as show
`ma cos alpha = mg sin alpha`
`a = (g sin alpha)/(cos alpha) = g tan alpha`
.
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