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A light string passing over a smooth lig...

A light string passing over a smooth light pulley connects two blocks of masses `m_1` and `m_2` (vertically). If the acceleration of the system is `g//8`, then the ratio of the masses is

A

`8:1`

B

`9:7`

C

`4:3`

D

`5:3`

Text Solution

Verified by Experts

The correct Answer is:
b

In the given system, `a =(m_(1) -m_(2)g)/(m_(1) + m_(2)) =(g)/(8)`
`:. (m_(1)-m_(2))/(m_(1) +m_(2)) =(1)/(8)`
`8m_(1) -8m_(2) = m_(1) + m_(2)`
`7 m_(1) = 9m_(2)`
`(m_(1))/(m_(2)) = (9)/(7)` .
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