A block is gently placed on a conveyor b...

A block is gently placed on a conveyor belt moving horizontal with constant speed After `t = 4s` the velocity of the block becomes equal to velocity of the belt If the coefficient of friction between the block and the belt is `mu = 0.2`, then the velocity of the conveyor belt is .

`8//s`

`6m//s`

`4m//s`

`2m//s`

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The correct Answer is:

On account of friction `(a =mu g)` velocity of block will become equal to velocity of block will become equal to velocity of conveyor belt and the relative motion between the two will stop
`upsilon = at = mu g t =0.2 xx 10 xx 4 = 8m//s` .

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