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The coefficient of static friction mu(s)...

The coefficient of static friction `mu_(s)` between block A of mass `2kg` and the table as shown in is 0.1 What would be the maximum mass value of blocks `B` so that the two bloks do not move ? The string and the pulley are assumed to be smooth and massless `(g = 10m//s^(2))`
.

A

`0.2kg`

B

`0.4kg`

C

`2.0kg`

D

`4.0kg`

Text Solution

Verified by Experts

The correct Answer is:
a
Here, `m_(1) = 2kg, m_(2) = ?`
The two blocks would not move, when
`T = m_(2) g = f_(s) = mu_(s) R = mu_(s) m_(1) g`
`:. M_(2) = mu_(s) m_(1) = 0.1 xx 2 = 0.2kg` .
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