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A system consists of three masses `m_(1)` , `m_(1)` , `m_(1)` , `m_(2)` and `m_(3)` connected by a string passing over a pulley `P` . The mass `m_(1)` hangs freely and `m_(2)` and `m_(3)` are on a rough horizontal table (the coefficient of friction=mu) The pulley is frictionless and of negligible mass. The downward acceleration of m`1` is (Assume `m_(1)=m_(2)=m_(3)=m`).

A

`g(1-3mu)/(9)m`

B

`(2gmu)/(3)`

C

`g (1-2mu)/(3)`

D

`g(1-2mu)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
c

Let a be the downward acceleration of mass m pulling force on all the three masses
`F = (m_(1) + m_(2) +m_(3))a`
force of friction on masses `m_(2)` and `m_(3)`
`f = mu (m_(2) + m_(3))g`
Equation of motion of mass `m_(1)` is
`(m_(1) + m_(2) + m_(3)) a = m_(1) g - mu (m_(2) + m_(3))g`
or `(m + m + m)a = mg - mu (m + m)g`
or `a = (mg (1 -2mu))/(3m) = g(1-2mu)/(3)` .
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