Friction between any two surfaces in contact is the force that opposes the relative motion between them The force of limiting friction (F) between any two surfaces in contact is directly proportional to the normal reaction (R) between them `F prop R` or `F = mu R` where `mu` is coefficient of limiting friction If `theta` is angle of friction then `mu = tan theta`
A force of `49N` is just able to move a block of wood weighing `10kg` on a rough horizontal surface The coefficient of friction is .

Options

A. `0.5`
B. `4.9`
C. `10//49`
D. `49//9.8`

Answer

a

Explanation

Here, `P = F = 49N,m = 10kg`
`mu = (F)/(R) = (F)/(mg) = (49)/(10 xx9.8) =0.5` .