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Friction between any two surfaces in co...

Friction between any two surfaces in contact is the force that opposes the relative motion between them The force of limiting friction (F) between any two surfaces in contact is directly proportional to the normal reaction (R) between them `F prop R` or `F = mu R` where `mu` is coefficient of limiting friction If `theta` is angle of friction then `mu = tan theta`
A force of `49N` is just able to move a block of wood weighing `10kg` on a rough horizontal surface The coefficient of friction is .

A

`0.5`

B

`4.9`

C

`10//49`

D

`49//9.8`

Text Solution

Verified by Experts

The correct Answer is:
a
Here, `P = F = 49N,m = 10kg`
`mu = (F)/(R) = (F)/(mg) = (49)/(10 xx9.8) =0.5` .
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Knowledge Check

  • Friction between any two surfaces in contact is the force that opposes the relative motion between them The force of limiting friction (F) between any two surfaces in contact is directly proportional to the normal reaction (R) between them F prop R or F = mu R where mu is coefficient of limiting friction If theta is angle of friction then mu = tan theta The angle of friction in the above question is .

    A
    `34^(@)26'`
    B
    `30^(@)`
    C
    `26^(@) 34'`
    D
    `45^(@)`

  • Friction between any two surfaces in contact is the force that opposes the relative motion between them The force of limiting friction (F) between any two surfaces in contact is directly proportional to the normal reaction (R) between them Fprop R or F = mu R where mu is coefficient of limiting friction If theta is angle of friction then mu = tan theta The acceleration produce in the block in the above question is .

    A
    `9.8ms^(-2)`
    B
    `0.3ms^(-2)`
    C
    `1.5ms^(-2)`
    D
    `4.9ms^(-2)`

  • Friction between any two surfaces in contact is the force that opposes the relative motion between them The force of limiting friction (F) between any two surfaces in contact is directly proportional to the normal reaction (R) between them F prop R or F = mu R where mu is coefficient of limiting friction If theta is angle of friction then mu = tan theta A horizontal force of 1.2kg is applied on a 1.5kg block which rests on a horizontal surface If the coefficient of friction is 0.3 force of friction is .

    A
    `0.45kgf`
    B
    `1.2kgf`
    C
    `1.5kgf`
    D
    `0.3kgf`

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