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A perosn is holding a bucket by applying...

A perosn is holding a bucket by applying a force of 20N. He moves a horizontal distance of 15m first and then climbs up a distance of 12m. What is the total work done by him?

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Here, `F=20N, s_(1)=15m, theta_(1)=90^(@)`
`s_(2)=12m, theta_(2)=0^(@), W=?`
`W=W_(1)+W_(2)=Fs_(1)costheta_(1)+Fs_(2)costheta_(2)`
`=20xx15cos90^(@)+20xx12cos0^(@)`
`W=0+240=240J`
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Knowledge Check

  • A man of mass 65 kg is holding a bucket of mass 15 kg. He walks 50 m on a level road at a constant speed of 3 m/s and then climbs up a hill of height 20 m. What is the work done by the man? Take g = 10 m/s^2 .

    A
    2.05kJ
    B
    3.5kJ
    C
    12kJ
    D
    16kJ

  • A person holds a bucket of weight 60N . He walks 7m along the horizontal path and then climbs up a vertical distance of 5m. The work done by the man is

    A
    300 J
    B
    420 J
    C
    720 J
    D
    None of these

  • A person holds a bucket of weight 60 N. He walks 7 m along the horizontal path and then climbs up a vertical distance of 5 m. The work done by the man is

    A
    `300 N-m`
    B
    `420 N-m`
    C
    `720 N-m`
    D
    `210 N-m`
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