A bullet of mass 10g travels horizontally with speed `100m//s` and is absorbed by a wooden block of mass 900 g suspended by a string. Find the vertical height through which the block rises. Given `g=10m//s^(2)`

Explanation

To solve the problem step by step, we will follow these steps:

### Step 1: Convert the masses to kilograms
The mass of the bullet (m) is given as 10 grams, and the mass of the wooden block (M) is given as 900 grams. We need to convert these masses into kilograms for our calculations.

\[ m = 10 \, \text{g} = \frac{10}{1000} \, \text{kg} = 0.01 \, \text{kg} \]
...