A spring of force constant 24N`//`m is resting on a frictionless horizontal surface. A force of 10N is applied on the block of mss 4kg at one end of the spring. What is the speed of the block when it has been moved through a distance of 0.5 m ?

Explanation

To solve the problem step by step, we will apply the work-energy principle and the concept of potential energy stored in the spring.

### Step 1: Identify the forces acting on the block
The forces acting on the block are:
- The applied force \( F = 10 \, \text{N} \)
- The spring force \( F_s = kx \) where \( k = 24 \, \text{N/m} \) and \( x \) is the extension of the spring
- The weight of the block \( mg \) and the normal force \( N \) (which do not do work since they act perpendicular to the displacement)

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