Two blocks`A` and`B` are connected to each other by a string and a spring , the spring pases and a frictionlesss pulley as down over in the figure . Block `B` sides over the horizental top surface of a strionry block `C` both with the verical side of `C` , both with the same conform speed

The coefficient of friction between the surface the of block is `0.2` force constant of the spring is `1960` newtons , if mass of block `A` is `2` kg , celculate the mass of block `F` and `B` and the energy stored is the spring

Explanation

A is clear form figure.
for block `A,T=2g,`
for block `B,T=f=muR=mumg`
`:. T=mumg or 2g=0.2mg, or m=10kg`
Also, `T=2g=2xx9.8=19.6N`
If x is extension produced in the spring,
`T=Kx or x=(T)/(K)=(19.6)/(1960)=0.01m`
Energy stored in the spring. ltbrlt `U=(1)/(2)Kx^(2)=(1)/(2)xx1960(0.01)^(2)=0.098J`