200 kg of water is heated from `20^(@)C` to `100^(@)C`. If specifice heat of water is `4.2xx10^(3)Jkg^(-1)0C^(-1)`, calculate the increase in the mass of water.

Explanation

Here, `m=200kg,`
`DeltaT=(100-20)^(@)C=80^(@)C`
`s=4.2xx10^(3)Jkg^(-1).^(@)C^(-1)`
Heat Energy absorbes, `E=smDeltaT`
`=(4.2xx10^(13))xx200xx80J`
`E=6.72xx10^(7)J`
Increase in mass of water,
`m=(E)/(C^(2))=(6.72xx10^(7))/((3xx10^(8))^(2))`
`m=7.46xx10^(-10)kg`