A standard car developes 40 H.P. Find the maximum speed the car can attain agains a resistance of 20kg wt. due to air and friction. Gvien efficiency of the engin is `25%.1H.P.=746W ` and `g=10ms^(-2)`.

Explanation

Here,
`P=40 H.P. =40xx746wat t`
`v=?F=20kg wt. =20xx10N`
`eta =25%, g=10m//s^(2)`
As ` eta=("output power")/("input power")`
`:.` output power = force `xx` velocity
`:. "velocity" =("output power")/("force")`
`v=(7460)/(20xx10)=37.3m//s`