A particle of mass 0.1kg has an iniital speed of `4ms^(-1)` at a point A on a roudh horizontal road. The coefficient of friction between the object and road is 0.15. The particle moves to a point B at a distance of 2m from A. What is the speed of particle at B ?
Take `g=10ms^(-2)`

Explanation

Here,
`m=0.1kg, u=4ms^(-1), mu=0.15, v=?`
`s=2m, a=-mug=-0.15xx10=-1.5m//s^(2)`
From `v^(2)-u^(2)=2as`
`v^(2)=u^(2)+2as=4^(2)+2(-1.5)xx2=10`
`v=sqrt(10)=3.16m//s`