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A man moves on a straight horizontal road with a block of mass 2 kg in his hand. If he covers a distance of `40m` with an acceleration of `1ms^(-2)`, find the work done by the man.

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Here, `m=2kg, s=40m, a=1ms^(-2), W=?`
`W=Fxcos0^(@)=mas=2xx1xx40=80J`
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