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A man weighing 60kg f suports a body of ...

A man weighing `60kg` `f` suports a body of `20kg f ` on his head. Calculate work done by him in moving a distance of `15m` up an incline of `1` in 10 . Take `g=9.8m//s^(2)`

Text Solution

Verified by Experts

Here, `m=60kg+20kg=80kg`
`W=?s=15m, sintheta=(1)/(10),g=9.8ms^(2)`
`W=(mgsintheta)s=80xx9.8xx(1)/(10)xx15`
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Knowledge Check

  • The work done in dragging a stone of mass 100 kg up an inclined plane 1 in 100 through a distance of 10 m is ("takeg" = 9.8 m//s^(2))

    A
    zero
    B
    `980 J`
    C
    `9800 J`
    D
    `98 J`

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