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The string of a pendulum is 2.0m long. T...

The string of a pendulum is `2.0m` long. The bob is pulled sideways so that the string becomes horizontal and then the bob is released. What is the speed with which the bob arrives at the lowest point ? Assume theat `10%` of initial energy is dissipated against air resistance. Take `g=10m//s^(2)`

Text Solution

AI Generated Solution

To find the speed of the pendulum bob at the lowest point after being released from a horizontal position, we can follow these steps: ### Step 1: Understand the Initial Energy When the bob is pulled to the horizontal position, it has potential energy due to its height. The height (h) from which the bob is released is equal to the length of the string (L) since it is horizontal. - **Initial Potential Energy (PE_initial)** = mgh - Here, h = L = 2.0 m, and g = 10 m/s². ...
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Knowledge Check

  • The bob of a pendulum is released from a horizontal position. If the length of pendulum is 2 m, what is the speed with which the bob arrives at the lower most point. Assume that 10% of its energy is dissipated against air resistance. (Take g = 10 m s^(-2) )

    A
    `4 m s^(-1)`
    B
    `6 m s^(-1)`
    C
    `8 m s^(-1)`
    D
    `10 m s^(-1)`

  • A pendulum bob on a 2 m string is displaced 60^(@) from the vertical and then released. What is the speed of the bob as it passes through the lowest point in its path

    A
    `sqrt(2)m//s`
    B
    `sqrt(9.8) m//s`
    C
    `4.43 m//s`
    D
    `1//sqrt(2) m//s`

  • A pendulum bob on a 2 m string is displaced 60^(@) from the verticle and then released . What is the speed of the bob as it passes through the lowest point in its path?

    A
    `sqrt2 m//s`
    B
    `sqrt 9.8 m//s`
    C
    `4.43 m//s`
    D
    `1//sqrt2 m//s`

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