A spring of force constant 24N`//`m is resting on a frictionless horizontal surface. A force of 10N is applied on the block of mss 4kg at one end of the spring. What is the speed of the block when it has been moved through a distance of 0.5 m ?

Explanation

Here, `K=24N//m, m=4kg`
`F=10N,x=0.5m`
Work done on the spring `=` gain in KE `+` gain in PE
`:. Fx=(1)/(2)m upsilon^(2)+(1)/(2)Kx^(2)`
`10xx0.5=(1)/(2)xx4 upsilon^(2)+(1)/(2)xx24(0.5)^(2)`
`2upsilon^(2)=5-3=2,upsilon^(2)=1, upsilon=1m//s`