Show that energy equivalent of one atomic mass unit is nearly `933MeV`.
Take `1a m u=1.66xx10^(-27)kg`

Explanation

Here, `E=?m=1am u=1.66xx10^(-27)kg`
`E=mc^(2)=1.66xx10^(-27)(3xx10^(8))^(2)`
`=14.94xx10^(-11)J`
`=(14.94xx10^(-11))/(1.6xx10^(-13))MeV`
`=933.75MeV`