An elevator which can carry a maximum load of `1800kg` is moving with a constant speed of `2ms^(-1)`. The frictional force opposing the motino is `5000N`. Calculate the minimum power delivered by the motor to the elevator in watt and hp ?
Take `g=10m//s^(2)`

Explanation

Here, `m=1800kg, upsilon=2ms^(-1),`
`f=5000N,P=?`
Minimum force required to be applied,
`F=mg+f=1800xx10+5000=23000N`
`P=Fxxupsilon=23000xx2=46000W=46kW`
`=(46000)/(746)hp=61.66hp`