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Find the power of a person who can chew ...

Find the power of a person who can chew `30g` of ice in one minute. Latent heat of ice `=80cal//gm`, `J=4.2`joule`//`cal.

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Mass of ice chewe, `m=30g`
time taken,`=1min=60s.`
Latent heat of ice, `L=80cal//g`
Heat produced `=mL=30xx80=2400cal`.
`=2400xx4.2J.`
Power `=("work")/("time")=(2400xx4.2)/(60)"watt"=168 "watt"`
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