An engine of weight `6.5` metric ton is going up an inclined plane of 5 in 13 at the rate of `9km//h`. If the coefficient of friction is `(1)/(120`. Calculate the power of the engine. Take `g=9.8m//s^(2)`

Explanation

To solve the problem of calculating the power of the engine going up an inclined plane, we can follow these steps:

### Step 1: Convert the weight of the engine to Newtons
The weight of the engine is given as 6.5 metric tons. We need to convert this to kilograms and then to Newtons using the formula:
\[ \text{Weight (W)} = \text{mass (m)} \times g \]
Where \( g = 9.8 \, \text{m/s}^2 \).
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