A mass of `5kg` is moving along a circular path or radius `1m`. If the mass moves with 300 revolutions per minute, its kinetic energy would be

Options

A. `250pi^(2)`
B. `100pi^(2)`
C. `5pi^(2)`
D. `0`

Answer

A

Explanation

Here, `m=5kg, r=1m`
`omega=(300)/(60)rps=5rps=5xx2pirads^(-1)`
`K.E.=(1)/(2)m upsilon^(2)=(1)/(2)m(romega)^(2)=(1)/(2)xx5(1xx10pi)^(2)=250pi^(2)J`