A long spring when stretched by `x cm`, has a potential energy `U`. On increasing the stretching to `nx cm,` the potential energy stored in spring will be

Options

A. `U//n`
B. `Nu`
C. `n^(2)U`
D. `U//n^(2)`

Explanation

To solve the problem, we need to understand how the potential energy stored in a spring changes with the amount of stretch or compression. We will use Hooke's law and the formula for potential energy stored in a spring.

### Step-by-Step Solution:

1. **Understand the Formula for Potential Energy in a Spring**:
The potential energy \( U \) stored in a spring when it is stretched or compressed by a distance \( x \) is given by the formula:
\[
U = \frac{1}{2} k x^2
...