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At sea level, a N(2), molecule in air ha...

At sea level, a `N_(2)`, molecule in air has an average translational `KE=6.2xxx10^(-21)J`. Its mass is `4.7xx10^(-26)kg.` If the molecule shoots up straight without any resistance, it will risw to a height of

A

`135km`

B

`13.5km`

C

`1.35 km`

D

`1350 km`

Text Solution

Verified by Experts

The correct Answer is:
B
Here,`K.E.=6.2xx10^(21)J, m=4.7xx10^(-26)kg`
As `KE` of molecule will get converted into its `PE` as the water level rise.
`:. PE=6.2 xx10^(21)J=mgh`
or `h=(6.2xx10^(-21))/(mg)=(6.2xx10^(-21))/(4.7xx10^(-26)xx98)`
`~~13.5xx10^(3)m =13.5km`
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