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The block of mass M moving on the frict...

The block of mass `M` moving on the frictionless horizontal surface collides with the spring constant `k` and compresses it by length `L` . The maximum momentum of the block after collision is

A

`(ML^(2))/(K)`

B

zero

C

`(KL^(2))/(2M)`

D

`Lsqrt(MK)`

Text Solution

Verified by Experts

The correct Answer is:
D
Energy `=(1)/(2) KL^(2) =(p^(2))/(2M), p=Lsqrt(M)`
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