Home
Class 11
PHYSICS
The potential energy of a partical of ma...

The potential energy of a partical of mass `2 kg` moving in `y-z` plane is given by `U=(-3y+4z)J` where `y` and `z` are in metre. The magnitude of force ( in newton ) on the particle is `:`

Text Solution

Verified by Experts

Here, `U=(-3 y + 4 z)J`
As `vec(F)=-(deltau)/( deltay)hat(j)- (deltau)/( deltaz) hat(k)`
`:. vec(F) 3 hat (j) - 4 hat(k)`
`|vec(F)|=sqrt(3^(2)+(-4)^(2))=sqrt(9+16)=5N`
Promotional Banner

Topper's Solved these Questions

  • WORK, ENERGY AND POWER

    PRADEEP|Exercise Assertion-Reason Type Questions|24 Videos

  • WORK, ENERGY AND POWER

    PRADEEP|Exercise Comprehension|9 Videos

  • THERMODYNAMICS

    PRADEEP|Exercise Assertion- Reason Type Questions|19 Videos

Similar Questions

Explore conceptually related problems

The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=(-7x+24y)J , where x and y are given in metre. If the particle starts from rest, from the origin, then the speed of the particle at t=2 s is

The potential energy of a particle of mass 1 kg moving in X-Y plane is given by U=(12x+5y) joules, where x an y are in meters. If the particle is initially at rest at origin, then select incorrect alternative :-

The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=-7x+24y joule, x and y being in metre. Initially at t = 0 the particle is at the origin. (0, 0) moving with a velocity of 6[2.4hat(i)+0.7hat(j)]m//s . The magnitude of force on the particle is :

The potential energy of a particle of mass 5 kg moving in xy-plane is given as U=(7x + 24y) joule, x and y being in metre. Initially at t=0 , the particle is at the origin (0,0) moving with velovity of (8.6hati+23.2hatj) ms^(1) , Then

The potential energy (in joules ) function of a particle in a region of space is given as: U=(2x^(2)+3y^(2)+2x) Here x,y and z are in metres. Find the maginitude of x compenent of force ( in newton) acting on the particle at point P ( 1m, 2m, 3m).

The potential energy U in joule of a particle of mass 1 kg moving in x-y plane obeys the law U = 3x + 4y , where (x,y) are the co-ordinates of the particle in metre. If the particle is at rest at (6,4) at time t = 0 then :