A bomb of mass `16 kg ` at rest explodes into two pieces of masses `4kg` and `12kg`. If KE of `4 kg` mass is `288 J`, what is the velocity (in `ms^(-1)` of the other piece of `12 kg` ?

Explanation

Here, `m_(1)=4 kg, m_(2)=12 kg `
`E_(1)=(1)/(2) m_(1)upsilon_(1)^(2)`
`288=(1)/(2) xx4 upsilon_(1)^(2), upsilon_(1)=sqrt((288)/( 2))=12 m//s`
According to principle of conservation of linear momentum, `m_(1)upsilon_(1)+m_(2)upsilon_(2)=0`
`upsilon_(2)=(-m_(1)upsilon_(1))/( m_(2))`,
`upsilon_(2)=(-4xx12)/( 12)`=-4 m//s`