Three particles of masses `0.2 kg, 0.3 kg` and `0.4 kg` are situated at the vertices `A,B` and `C` of a right angled traingle `ABC` with `/_A = 90^(@) , AB = 2 cm` along X-axis and `BC = 2.5 cm`. Find the distance of centre of mass from `A`.

Explanation

To find the distance of the center of mass from point A in the given problem, we will follow these steps:

### Step 1: Define the coordinates of the points
We have a right-angled triangle ABC with:
- Mass \( m_1 = 0.2 \, \text{kg} \) at point A (0, 0)
- Mass \( m_2 = 0.3 \, \text{kg} \) at point B (0, 2) (since AB = 2 cm along the Y-axis)
- Mass \( m_3 = 0.4 \, \text{kg} \) at point C (1.5, 2) (we will find the x-coordinate of C using the Pythagorean theorem)

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