A particle performing uniform circular motion has angular frequency is doubled & its kinetic energy halved, then the new angular momentum is

Explanation

`L = m v r and v = r omega = r(2pi n)`
`r = (v)/(2pin)`
`:. L = m v((v)/(2pin)) = (m v^(2))/(2pin)`
As `K.E. = (1)/(2) m v^(2)`, therefore, `L = (K.E.)/(pi n)`
when `K.E.` is halved and frequency `(n)` is
doubled, `L' = (K.E.')/(pi n') = (K.E.//2)/(pi(2n)) = (K.E.)/(4pi n) = (L)/(4)`
i.e. angular momentum becomes one fourth.