A wheel of mass `10 kg` and radius of gyration `25 cm` is rotating at `600` rpm. What is its moment of inerta ?

Explanation

Here, `M = 10 kg, K = 25 cm = (1)/(4)m, n = (600)/(60)rps = 10 rps. 1 = ?`
`I= MK^(2) = 10 ((1)/(4))^(2) = 0.625 kg m^(2)`