Calculate moment of inertia of a uniform circular ring of mass `1.5 kg` and diameter `50 cm` about a diameter of the ring.

Explanation

Here, `M = 1.5 kg, R = 50//2 = 25 cm = (1)/(4)`
About a diameter of the ring. Moment of inertia, `I = (1)/(2)MR^(2) = (1)/(2)xx1.5 xx ((1)/(4))^(2) = 0.047 kg m^(2)`