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Calculate moment of inertia of a uniform...

Calculate moment of inertia of a uniform circular ring of mass `1.5 kg` and diameter `50 cm` about a diameter of the ring.

Text Solution

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Here, `M = 1.5 kg, R = 50//2 = 25 cm = (1)/(4)`
About a diameter of the ring. Moment of inertia, `I = (1)/(2)MR^(2) = (1)/(2)xx1.5 xx ((1)/(4))^(2) = 0.047 kg m^(2)`
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Knowledge Check

  • Moment of inertia of a uniform circular ring of mass 2 kg and diameter 1 m about its diameter is

    A
    `0.25 kg m^(2)`
    B
    `0.5 kg m^(2)`
    C
    `1 kg m^(2)`
    D
    `2 kg m^(2)`

  • The moment of inertia of a uniform circular disc of mass M and of radius R about one of its diameter is

    A
    `(1)/(4) MR^(2)`
    B
    `(1)/(2) MR^(2)`
    C
    `(2)/(3) MR^(2)`
    D
    `(2)/(5) MR^(2)`

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