The moment of inertia of a soild sphere about a tangent is `(5)/(3)mr^(2)`. What would be its moment of inertia about its diameter.

Explanation

To find the moment of inertia of a solid sphere about its diameter, given that the moment of inertia about a tangent is \( \frac{5}{3} m r^2 \), we can use the parallel axis theorem. Here’s a step-by-step solution:

### Step 1: Understand the Given Information
We know the moment of inertia of the solid sphere about a tangent is given by:
\[ I_{tangent} = \frac{5}{3} m r^2 \]
We need to find the moment of inertia about its diameter, denoted as \( I_{diameter} \).
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