Find radius of gyration of a rod of length `l` and mass `m` about an axis perpendicular its length through one end.

Explanation

Here, `K = ?`
According to theorem of parallel axes,
`I_(end) = I_(cm) + m(l//2)^(2) = (ml^(2))/(12) + (ml^(2))/(4) = (ml^(2))/(3)`
`:.mK^(2) = (ml^(2))/(3) or K = (l)/(sqrt(3))`