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Find the torque of a force (7 hati + 3ha...

Find the torque of a force `(7 hati + 3hatj - 5hatk)` about the origin. The force acts on a particle whose position vector is `(hati - hatj + hatk)`.

Text Solution

AI Generated Solution

To find the torque of a force about the origin, we can use the formula for torque, which is given by: \[ \text{Torque} (\tau) = \mathbf{R} \times \mathbf{F} \] where: - \(\mathbf{R}\) is the position vector of the particle, ...
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(i) Find the torque of a force 7hati + 3hatj - 5hatk about the origin. The force acts on a particle whose position vector is hati - hatj + hatk . (ii) Show that moment of a couple does not depend on the point about which you take the moments.

Find the torque of a force (5 hati - 2 hatj + 3 hatk) about the origin, which acts on a particle whose position vector is ( hati - hatj + hatk) .

Knowledge Check

  • What is the torque of a force 3hati+7hatj+4hatk about the origin, if the force acts on a particle whose position vector is

    A
    `hati - 5hatj + 8 hatk`
    B
    `2hati + 2hatj + 2hatk`
    C
    `hati + hatj + hatk`
    D
    `3hati + 2hatj + 3hatk`

  • What is the torque of a force 3hati+7hatj+4hatk about the origin if the force acts on a particle whose position vector is 2hati+2hatj+1hatk ?

    A
    `hati-hatj+8hatk`
    B
    `2hati+2hatj+2hatk`
    C
    `hati+hatj+hatk`
    D
    `3hati+2hatj+3hatk`

    • Similar Questions

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    Find the torque of a force (5 hati - 2 hatj + 7 hatk) about the origin, which acts on a particle whose position vector is (2 hati - hatj + hatk) .

    Find the torque of a force 7hati - 3hatj - 5hatk about the origin which acts on a particle whose position vectors is hati + hatj - hatk

    Find the torque about the origin when a force of 3 hatj N acts on a particle whose position vector is 2 hatk m

    Find the torque about the origin when a force of 3 hatj N acts on a particle whose position vector is 2 hatkm.

    Find the torque of a force vecF= -3hati+hatj+5hatk acting at the point vecr=7hati+3hatj+hatk

    Find the torque of a force F=a(hati+2hatj+3hatk) N about a point O. The position vector of point of application of force about O is r=(2hati+3hatj-hatk) m .

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