Calculate moment of inertia of a circular disc about a transverse axis through the centre of the disc. Given, diameter of disc is `40 cm`, thickness `= 7 cm` and density of material of disc `= 9 g cm^(-3)`.

Explanation

To calculate the moment of inertia of a circular disc about a transverse axis through its center, we can follow these steps:

### Step 1: Identify Given Values
- Diameter of the disc, \( D = 40 \, \text{cm} \)
- Radius of the disc, \( R = \frac{D}{2} = \frac{40}{2} = 20 \, \text{cm} = 0.2 \, \text{m} \)
- Thickness of the disc, \( t = 7 \, \text{cm} = 0.07 \, \text{m} \)
- Density of the material, \( \rho = 9 \, \text{g/cm}^3 = 9 \times 10^3 \, \text{kg/m}^3 \)

...