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Three identicle particle each of mass 1 ...

Three identicle particle each of mass `1 kg` are placed with their centres on a straight line. Their centres are marked `A, B and C` respectively. The distance of centre of mass of the system from `A` is.

A

`(PQ + PR + QR)/(3)`

B

`(PQ + PR)/(3)`

C

`(PQ + QR)/(3)`

D

`(PQ + QR + PR)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
Clearly `CM` of the system is at `Q`, its distance from `P`, i.e.
`PQ = (mxx0+mxxPQ+mxxPR)/(3m) = (PQ + PR)/(3)`
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