Home
Class 11
PHYSICS
A small object of uniform density rolls ...

A small object of uniform density rolls up a curved surface with an initial velocity v. it reaches up to a maximum height of `(3v^2)/(4g)` with respect to the initial position. The object is

A

Circular Disc

B

Ring

C

Solid sphere

D

Hollow sphere

Text Solution

Verified by Experts

The correct Answer is:
A
Applying the principle of conservation of mechanical energy,
`mgh = (1)/(2)mv^(2) (1 + (K^(2))/(R^(2)))`
`mg ((3v^(2))/(4g)) = (1)/(2)mv^(2) (1 + (K^(2))/(R^(2)))`
`(3)/(4)mv^(2) - (1)/(2) mv^(2) = (1)/(2)mv^(2) ((K^(2))/(R^(2)))`
`(K^(2))/(R^(2)) = (1)/(2)`
`:.` The object must be a circular disc.
Promotional Banner

Similar Questions

Explore conceptually related problems

A small object of uniform density rolls up a curved surface with an initial velocity 'w'. It reaches up to a maximum height of (3u^(2))/(4g) with respect to initial position. The object is:

A small object of uniform density rolls up a curved surface with an initial velocity v . It reached upto maximum height of 3v^(2)//4g with respect to the initial position. The object is - .

A small object of uniform density rolls up a curved surface with an initial velocity v. It reaches up to a maximum height of 5v2 / 6g with respect to the initial position. The object is- О. o ring O solid sphere O hollow sphere o disc

When a body thrown vertically up with an initial velocity vo ,then maximum height reached by the body is

An object of radius R and mass M is rolling horizontally without slipping with speed v . It then rolls up the hill to a maximum height h = (3v^(2))/(4g) . The moment of inertia of the object is ( g = acceleration due to gravity)

For a body thrown vertically up with an initial velocity u ,the maximum height reached by body from the ground is

When a ball is thrown up vertically with velocity v_0 , it reaches a maximum height of h. If one wishes to triple the maximum height then the ball should be thrown with velocity