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Two stone of masses m and 2 m are whirle...

Two stone of masses `m and 2 m` are whirled in horizontal circles, the heavier one in a radius `r//2` and the lighter one in radius `r`. The tangential speed of lighter stone is `n` times that of the value of heavier stone when thy experience same centripetal forces. the value of `n` is

A

`1`

B

`2`

C

`3`

D

`4`

Text Solution

Verified by Experts

The correct Answer is:
B
Centripetal force `= (Mv^(2))/(r )`
As per question `(m(n v)^(2))/(r ) = (2mv^(2))/((r//2))`
or `n^(2) = 4 or n = 2`
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