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A body of mass 0.1 kg is suspended at a ...

A body of mass `0.1 kg` is suspended at a height of `1 m` about the ground by a weightless string which passes over a frictionless pulled, Fig. The velocity with which the body strikes the ground is

A

`(11)/(20)ms^(-1)`

B

`(20)/(11) m//s`

C

`(10)/(11)ms^(-1)`

D

`(11)/(10)ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Applying the law of conservation of enrgy
`mgh = (1)/(2)mv^(2) + (1)/(2)I omega^(2)`
`= (1)/(2)mv^(2) + (1)/(2) ((1)/(2)MR^(2))(v^(2))/(R^(2))`
`= (1)/(2) (m + (M)/(2))v^(2)`
`v = (2gh)/((1+M//2m)) = (2 xx 10 xx 1)/((1+2//0.2)) = (20)/(11)ms^(-1)`
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