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A flywheel of moment of inertia 3 xx 10^...

A flywheel of moment of inertia `3 xx 10^(2) kg m^(2)` is rotating with uniform angular speed of `4.6 rad s^(-1)`. If a torque of `6.9 xx 10^(2)Nm` retards the wheel, then the time in which the wheel comes to rest is

A

`1.5 s`

B

`2 s`

C

`0.5 s`

D

`1 s`

Text Solution

Verified by Experts

The correct Answer is:
B
Here, `I = 3 xx 10^(2) kg m^(2), omega_(1) = 4.6 rad s^(-1)`
`tau = 6.9 xx 10^(2) Nm, omega_(2) = 0, t = ?`
`alpha = (tau)/(I) = (-6.9 xx 10^(2))/(3 xx 10^(2)) = - 2.3 rad//s^(2)`
From `omega_(2) = omega_(1) + alpha t`
`0 = 4.6 - 2.3 t, t = 2 sec`
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