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A boy is pushng a ring of mass 2kg and r...

A boy is pushng a ring of mass 2kg and radius 0.5 m with a stick as shwon in figure. The stick applies a force of 2N on the ring and rolls it without slipping with an accelertaion of `0.3 m/s^2.` The coefficinet of friction between the ground and the ring is large enough that rolling always occurs and the coefficient of friction between the stick and the ring of (P/10). The value of P is

A

`3`

B

`4`

C

`5`

D

`6`

Text Solution

Verified by Experts

The correct Answer is:
B

Refer to Fig.
`2 - f_(s) = Ma`
or `f_(s) = 2 - Ma = 2 - 2 xx 0.3 = 1.4 N`

Taking torque about `C`, we have
`f_(s)R - f_(k)R = I alpha == MR^(2) xx (1)/(R ) Mra`
or `1.4 xx 0.5 - f_(k) xx 0.5 = 2 xx 0.5 xx 0.3`
or `f_(k) = 1.4 - 0.6 = 0.8 N`
If `mu` is the coefficient of kinetic friction, then
`f_(k) = mu xx2 or mu = (f_(k))/(2) = (0.8)/(2) = 0.4 = (4)/(10)`
As per question, `(P)/(10) = (4)/(10) or P = 4`
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