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One quarter sector is cut from a uniform...

One quarter sector is cut from a uniform circular disc of radius R. This sector has mass M. it is made to rotate about a line perpendicular to its plane and passing through the center of the original disc. Its moment of inertia about the axis of rotation is

A

`(1)/(2)MR^(2)`

B

`(1)/(4)MR^(2)`

C

`(1)/(8)MR^(2)`

D

`sqrt(2)MR^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
As mass of quarter sector of disc is `M//4`, therefore, its moment of inertia about the given axis is
`I = (1)/(2) ((M)/(4))R^(2) = (1)/(8)MR^(2)`
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