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A circular disc of radius r is rolling w...

A circular disc of radius `r` is rolling without slipping on a horizontal surface. What is the ratio of the translational `KE` and rotational `KE` of disc ?

Text Solution

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The correct Answer is:
`(2)`
`KE` of translation, `KE_(T) = (1)/(2)mv^(2)`
`KE` of rotation, `KE_(R ) = (1)/(2)I omega^(2)`
`= (1)/(2) ((1)/(2)mr^(2)) omega^(2) = (1)/(4)mv^(2)`
`(KE_(T))/(KE_(R )) = ((1)/(2)mv^(2))/((1)/(4)mv^(2)) = 2`
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