If the parabola `y^2=4ax` passes through the centre of the circle `x^2+y^2 +4x-12y-4= 0,` what is the length of the latus rectum of the parabola

If the parabola y^(2) =4ax passes through the centre of the circle x^(2) +y^(2) + 4x - 12 y - 4 = 0 what is the length of the latus rectum of the parabola ?

Find the length of the Latus rectum of the parabola y^(2)=4ax .

Find the length of latus rectum of the parabola x^(2)=4x-4y .

The parabola y^(2) = 2ax passes through the centre of the circle 4x^(2) + 4y^(2) - 8x + 12 y - 7 = 0 . Find the focus the length of the latus rectum and the equation of the directrix of this parabola .

The parabola y^(2)=4ax passes through the centre of the circle 2x^(2)+2y^(2)-4x+12y-1=0; find the co- ordinates of the focus,length of the latus rectum and equation of the directrix.

The parabola y^(2) = 4ax passes through the centre of the circle 2x^(2) + 2y^(2) + 4 x- 12 y - 4 = 0 ,Find the coordinates of the focus , length of the latus rectum and equation of the derectrix

The length of the latus rectum of the parabola y^(2)+8x-4y-4=0 .

The length of the latus rectum of the parabola x^2 −4x−8y+12=0 is