The corner points of the feasible region determined by the system of linear contraints are (0,0), (0,40),( 20,40),(60,20),(60,0). The objective function is Z=4x+3y. Compare the quantity in Column A and Column B.

The corner points of the feasible region determined by the system of linear constraints are (0,0), (0,40), (20,40), (60, 20), (60, 0). The objective function is Z = 4x + 3y. Compare the quantity in column in A and column B. Column A= Maximum of Z Column B= 325

The corner points of the feasible region determined by the system of linear constraints are (0, 0), (0, 40), (20, 40), (60, 20), (60, 0). The objective function is z = 4x + 3y. Compare the quantity in Column A and Column B

The corner points of the feasible region determined by the system of linear constraints are (0, 0), (0, 40). (20, 40), (60, 20). (60, 0). "The objective function is Z = 4x + 3y . Compare the quantity in Column A and Column B. {:("Column A", "Column B"),("Maximum of Z",325):}

The corner points of the feasible regon determined by the system of linear inequalities constrains are (0,0),(0,40),(20,40),(60,0). The objective function is z=4x+3y. Compare the quantity in column A and colum B.

The corner points of a feasible region determined by a system of linear inequalities are (20,40),(50,100),(0,200) and (0,50). If the objective funtion Z=x+2y , then maximum of Z occurs at.

The corner points of a feasible region determined by a system of linear inequations are (0, 0), (4,0), (5,2), (2, 2) and (0, 1). If the objective function is Z = x + y, then maximum of Z occurs at:

The corneer points of a feasible region, determined by a system of linear inequations, are (0,0),(1,0),(4,3),(2,1) and (0,1). If the objective function is Z = 2x - 3y, then the minimum value of Z is :

The corner points of the feasible region determined by the system of linear constraints are (0,10) , (5,5) (25,20),(0,30) Let z = px + qy , where p,qgt0 Condition on p and q so that te maximum of z occurs at both the points (25,20 ) and (0,30) is ………