Let `f, g and h` be the lengths of the perpendiculars from the circumcenter of `Delta ABC` on the sides a, b, and c, respectively. Prove that `(a)/(f) + (b)/(g) + (c)/(h) = (1)/(4) (abc)/(fgh)`

Let f, g and h be the lengths of the perpendiculars from the circumcentre of DABC on the sides a, b and c , respectively, and a/f + b/g + c/h = 1/lambda (abc)/(fgh) , then lambda is

Let f,g,h be the lengths of the perpendiculars from the circumcenter of the Delta ABC on the sides BC,CA and AB respectively.If (a)/(f)+(b)/(g)+(c)/(h)=lambda(abc)/(fgh), then the value of 'lambda' is (B) (1)/(2) (B) (1)/(2) (D) (1)/(2) (D) 2

If the lengths of the sides vec(BC), vec(CA) and vec(AB) of the triangle ABC be a:b:c respectively and the lengths of perpendicular from the circumcenter upon vec(BC), vec(CA) and vec(AB) be x, y, z respectively, then prove that, a/x + b/y + c/z = (abc)/(4xyz) .

If x,y,z are respectively perpendiculars from the circumcentre on the sides of the Delta ABC, the value of (a)/(x)+(b)/(y)+(c)/(z)-(abc)/(4xyz)=

If h be the length of the perpendicular drawn from A on BC in the triangle ABC, show that, h=(a sin B sin C)/(sin(B+C)) .

AD, BE and CF are the medians of triangle ABC whose centroid is G. If the points A, F, G and E are concyclic, then prove that 2a^(2) = b^(2) + c^(2)

AD, BE and CF are the medians of triangle ABC whose centroid is G. If the points A, F, G and E are concyclic, then prove that 2a^(2) = b^(2) + c^(2)

AD, BE and CF are the medians of triangle ABC whose centroid is G. If the points A, F, G and E are concyclic, then prove that 2a^(2) = b^(2) + c^(2)