`3^(-5)times10^(-4)times(5^(4))/(5^(2))times6^(-5)=`

(3^(-5)times10^(-5)times125)/(5^(-7)times6^(-5))

(5^(-3)times a^(3)times c^(4))/(5^(2)times a^(-4)times c^(3))

(-4)^(-2)times(5)^(-3)times(5)^(-4)

(4^(5)times a^(8)times b^(3))/(4^(5)times a^(5)times b^(2))

Simplify: 10^(-1)times10^(2)times10^(-3)times10^(4)times10^(-5)times10^(6)

((5^(3))^(-2)times(5^(2))^(-3)times(6)^(5))/((2)^(3)times(3)^(2)times(5)^(5))

(5^(4)times x^(8)times y^(5))/(4^(5)times x^(5)y^(2))

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

((2)/(3))^(4)times((3)/(2))^(5)times((5)/(3))^(-2)times((3)/(5))^(-3)