`lim_(x-gtoo\ a t o p x-gtoo)(1+lambda/x+mu/(x^2))^(2x)=e^4t h e nlambda=(mu in R)`

if lim_(x rarr oo)(1+(lambda)/(x)+(mu)/(x^(2)))^(2x)=e^(2) then

lim_(x->pi)(2-lambda/x)^(2tan((pipi)/(2lambda)))=1/e, then lambda is equal to -

lim_(x rarr oo)x(tan^(-1)((x+lambda)/(x+mu))-(pi)/(4))=1, then ordered pair (lambda,mu) can be

lim_(x to oo)(int_0^(2x) te^(t^(2))dt)/(e^(4x^(2))) equals

lim_(x to oo)(int_0^(2x) te^(t^(2))dt)/(e^(4x^(2))) equals

If (lim)_(xvec0)(a e^x+bcos x+c e^(-x))/(e^(2x)-2e^x+1)=4,t h e n a. a=2 b. b=-4 c. c=2 d. a+b+c=-8

If (lim)_(xvec0)(a e^x+bcos x+c e^(-x))/(e^(2x)-2e^x=1)=4,t h e n a=2 b. b=-4 c. c=2 d. a+b+c=-8

The number of real roots of the equation 4x^(3)-x^(2)+lambda^(2)x-mu=0 , mu in R, lambda > 1 is

lim_(x->oo)x(a r c t a n(x+1)/(x+2)-a r c t a n x/(x+2)) is equal to

If x_(1),x_(2),...x_(2018) are in H.P.,x_(1)x_(2)+x_(2)x_(3)+......+x_(2017)x_(2018)=lambda and x_(1)x_(2018)=mu then the value of ((lambda)/(mu)) is equal to