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x + y = (4n + 3) pi /4, n in Z =>((1+...

` x + y = (4n + 3) pi /4, n in Z =>((1+tanx)(1+tany))/(tanxtany)=`

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x + y = (4n + 3) (pi) / (4), n in Z rArr ((1 + tan x) (1 + tan y)) / (tan x tan y) =

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If x + y + z = pi , tanx tany = 2 tanx + tany + tanz = 6 , then z equals :